$a, b, c, d$ are real numbers. The general solution of $\frac{d y}{d x}=\frac{a x+b}{c y+d}$ represents a…
$a, b, c, d$ are real numbers. The general solution of $\frac{d y}{d x}=\frac{a x+b}{c y+d}$ represents a family of straight lines, when
- $a=c=0$, and $b^2+d^2 \neq 0$
- $a \neq 0, c=0$ or $a=0, c \neq 0$
- $b d=0, a \neq 0, c \neq 0$
- $b+d=0, a+c=0$
Solution
$\begin{aligned} & \text { } \frac{d y}{d x}=\frac{a x+b}{c y+d} \\ & \qquad \int(c y+d) d y=\int(a x+b) d x \\ & \frac{c y^2}{2}+d y=\frac{a x^2}{2}+b x+k \text {, where } k \text { is constant of } \\ & \text { integration. } \\ & \text { For a family a straight line, } c=a=0 \text { and } \\ & b^2+d^2 \neq 0\end{aligned}$
Asked in: AP EAMCET 2022 (06 Jul Shift 2)
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