$\mathrm{CuSO}_{4}$ (aq.) $\stackrel{\mathrm{H}_{2} \mathrm{~S} \uparrow}{\longrightarrow} \mathrm{M}…

$\mathrm{CuSO}_{4}$ (aq.) $\stackrel{\mathrm{H}_{2} \mathrm{~S} \uparrow}{\longrightarrow} \mathrm{M} \downarrow \frac{\text { Excess }}{\text { of KCN }} \mathrm{N}+\mathrm{O}$
Then final products $\mathrm{N}$ and $\mathrm{O}$ are respectively.
  1. $\left[\mathrm{Cu}(\mathrm{CN})_{4}ight]^{3-},(\mathrm{CN})_{2}$
  2. $\mathrm{CuCN},(\mathrm{CN})_{2}$
  3. $\left[\mathrm{Cu}(\mathrm{CN})_{4}ight]^{2-},(\mathrm{CN})_{2}$
  4. $\mathrm{Cu}(\mathrm{CN})_{2}, \mathrm{~K}_{2} \mathrm{~S}$

Solution

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Asked in: JEE-TOPICTESTS-CHEMISTRY

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