Angular momentum of a single particle moving with constant speed along circular path :

Angular momentum of a single particle moving with constant speed along circular path :

remains same in magnitude but changes in the direction
remains same in magnitude and direction
is zero
changes in magnitude but remains same in the direction

Solution

The angular momentum is defined as the vector product of linear momentum and perpendicular distance,

\vec{L} = \vec{r} \times \vec{p} = \vec{r} \times m \vec{v}

, And direction will be upward & remain constant.

Asked in: JEE Main 2021 (31 Aug Shift 1)

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