Angle between the tangents to the circle $x^2+y^2=25 x^2$ from the point $(1,7)$ is
- $\frac{\pi}{4}$
- $\tan ^{-1}\left(\frac{2}{5}\right)$
- $\tan ^{-1} 2$
- $\frac{\pi}{2}$
Solution
$\begin{aligned} & \mathrm{OP}=5 \sqrt{2} \\ & \mathrm{OT}=5 \\ & \mathrm{PT}=\sqrt{\mathrm{OP}^2-\mathrm{OT}^2}=5 \\ & \Rightarrow \angle \mathrm{OPT}=45^{\circ} \\ & \Rightarrow \angle \mathrm{TPT}^{\prime}=2 \angle \mathrm{OPT}=2 \times 45^{\circ}=90^{\circ}\end{aligned}$Asked in: MHT CET 2022 (07 Aug Shift 2)