$6 \Omega$ and $12 \Omega$ resistors are connected in parallel. This combination is connected in series with a $10 \mathrm{~V}$ battery and $6 \Omega$ resistor. What is the potential difference between the terminals of the $12 \Omega$ resistor?

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Aicharya · Accepted Answer

$R=\frac{6 	imes 12}{6+12}=\frac{6 	imes 12}{18}=4 \Omega$ Total resistance, $R_{\mathrm{eq}}=6+4=10 \Omega$ Current, $\quad i=\frac{V}{R}=\frac{10}{10}=1 \mathrm{~A}$ The current in $12 \Omega$ resistor is $i_2=i\left(\frac{R_1}{R_1+R_2}ight)=1 	imes\left(\frac{6}{6+12}ight)$ $i_2=\frac{1}{3}$ The potential difference in $12 \Omega$ resistor $V=i R=\frac{1}{3} 	imes 12=4 \mathrm{~V}$

$6 \Omega$ and $12 \Omega$ resistors are connected in parallel. This combination is connected in series with…

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