$\mathrm{Xe}(\mathrm{g})$ and $\mathrm{F}_2(\mathrm{~g})$ reacted in the ratio $1: 20$ at $573 \mathrm{~K},…

$\mathrm{Xe}(\mathrm{g})$ and $\mathrm{F}_2(\mathrm{~g})$ reacted in the ratio $1: 20$ at $573 \mathrm{~K}, 60-70 \mathrm{bar}$, to form $\mathrm{A}$. When $\mathrm{A}$ is completely hydrolyzed, B and HF are formed. A and B are respectively
  1. $\mathrm{XeF}_2, \mathrm{O}_2$
  2. $\mathrm{XeF}_6, \mathrm{XeO}_3$
  3. $\mathrm{XeF}_4, \mathrm{XeOF}_4$
  4. $\mathrm{XeF}_4, \mathrm{XeO}_2 \mathrm{~F}_2$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2017 (25 Apr Shift 2)

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