$\frac{d^{2} y}{d x^{2}}=\sin x+e^{x} ; y(0)=3$ and $\frac{d y}{d x}$ at $x=0$ is 4 , then the equation of the

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$\frac{d}{d x}\left(\frac{d y}{d x}\right)=\sin x+e^{x}$ Integrating both sides.; $y \rightarrow \frac{d y}{d x}=e^{x}-\cos x+c$ at $x=0 ; \frac{d y}{d x}=4 ; \quad c=4$ $\frac{d y}{d x}=e^{x}-\cos x+4$ Integrating both sides; $y=e^{x}-\sin x+4 x+c$ put $x=0 ; y(0)=3$; $c=2$ Equation of curve $y=e^{x}-\sin x+4 x+2$

$\frac{d^{2} y}{d x^{2}}=\sin x+e^{x} ; y(0)=3$ and $\frac{d y}{d x}$ at $x=0$ is 4 , then the equation of the

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