$f: R \rightarrow R$ and $g: R \rightarrow R$ are two functions such that $f(x)=x^2$ and $g(x)=\frac{1}{x^2}$, then $x^4(f \circ g)(x)$ is equal to

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Aicharya · Accepted Answer

Given, $f(x)=x^2$ and $g(x)=1 / x^2$ $\begin{aligned} f \circ g(x) & =f(g(x))=\left(\frac{1}{x^2}ight)^2=\frac{1}{x^4} \ 	herefore \quad x^4 f \circ g(x) & =x^4 	imes \frac{1}{x^4}=1\end{aligned}$

$f: R \rightarrow R$ and $g: R \rightarrow R$ are two functions such that $f(x)=x^2$ and…

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