$\mathrm{Na}^{+}, \mathrm{Mg}^{2+}, \mathrm{Al}^{3+}$ and $\mathrm{Si}^{4+}$ are isoelectronic. The order of…

$\mathrm{Na}^{+}, \mathrm{Mg}^{2+}, \mathrm{Al}^{3+}$ and $\mathrm{Si}^{4+}$ are isoelectronic. The order of their ionic size is
  1. $\mathrm{Na}^{+}>\mathrm{Mg}^{2+} < \mathrm{Al}^{3+} < \mathrm{Si}^{4+}$
  2. $\mathrm{Na}^{+} < \mathrm{Mg}^{2+}>\mathrm{Al}^{3+}>\mathrm{Si}^{4+}$
  3. $\mathrm{Na}^{+}>\mathrm{Mg}^{2+}>\mathrm{Al}^{3+}>\mathrm{Si}^{4+}$
  4. $\mathrm{Na}^{+} < \mathrm{Mg}^{2+}>\mathrm{Al}^{3+} < \mathrm{Si}^{4+}$

Solution

Among the isoelectronic species, the cation having more positive charge would be the smaller in size.

Asked in: JEE-TOPICTESTS-CHEMISTRY

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