$\mathrm{N}_{2}$ and $\mathrm{O}_{2}$ are converted into monocations, $\mathrm{N}_{2}^{+}$ and…
$\mathrm{N}_{2}$ and $\mathrm{O}_{2}$ are converted into monocations, $\mathrm{N}_{2}^{+}$ and $\mathrm{O}_{2}^{+}$ respectively. Which of the following statements is wrong?
In $\mathrm{N}_{2}^{+}, \mathrm{N}-\mathrm{N}$ bond weakens
In $\mathrm{O}_{2}^{+}$, the $\mathrm{O}-\mathrm{O}$ bond order increases
In $\mathrm{O}_{2}^{+}$, paramagnetism decreases
$\mathrm{N}_{2}^{+}$ becomes diamagnetic
Solution
- (1) In \(\mathrm{N}_2^{+}, \mathrm{N}-\mathrm{N}\) bond weakens: This is correct. Bond order decreases, indicating a weaker bond.
- (2) \(\ln \mathrm{O}_2^{+}\), the \(\mathrm{O}-\mathrm{O}\) bond order increases: This is correct. Removing one electron from the antibonding orbital increases bond order.
- (3) \(\ln \mathrm{O}_2^{+}\), paramagnetism decreases: This is correct. Removal of one unpaired electron reduces paramagnetism.
- (4) \(\mathrm{N}_2^{+}\)becomes diamagnetic: This is incorrect. \(\mathrm{N}_2^{+}\)is still paramagnetic because it has one unpaired electron, despite its reduced bond order compared to \(\mathrm{N}_2\).