An X-ray tube produces a continuous spectrum of radiation with its shortest wavelength of $45 imes 10^{-2} Ã…$. The maximum energy of a photon in the radiation in $\mathrm{eV}$ is $\left(h=6.62 imes 10^{-34} \mathrm{~J}-\mathrm{s}, c=3 imes 10^8 \mathrm{~m} / \mathrm{s} ight)$

Question

An X-ray tube produces a continuous spectrum of radiation with its shortest wavelength of $45 	imes 10^{-2} Ã…$. The maximum energy of a photon in the radiation in $\mathrm{eV}$ is $\left(h=6.62 	imes 10^{-34} \mathrm{~J}-\mathrm{s}, c=3 	imes 10^8 \mathrm{~m} / \mathrm{s}ight)$

Aicharya · Accepted Answer

$\begin{aligned} E & =\frac{h c}{\lambda} \ & =\frac{6.62 	imes 10^{-34} 	imes 3 	imes 10^8}{45 	imes 10^{-12}} \ & =\frac{0.44 	imes 10^{-14}}{1.6 	imes 10^{-19}} \ & =0.275 	imes 10^5 \mathrm{eV}\end{aligned}$

An X-ray tube produces a continuous spectrum of radiation with its shortest wavelength of $45 \times 10^{-2}…

Solution