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An urn contains 3 black and 5 red balls. If 3 balis are drawn at random from the urn, the mean of the…
An urn contains 3 black and 5 red balls. If 3 balis are drawn at random from the urn, the mean of the probability distribution of the number of red balls drawn is
$\frac{45}{28}$ $\frac{15}{8}$ $\frac{2}{5}$ $\frac{3}{2}$
Solution
Let $X$ be number of red balls drawn.
\begin{array}{|c|c|c|c|c|}\hline \boldsymbol{X}=\boldsymbol{x} & 0 & 1 & 2 & 3 \\\hline \boldsymbol{P}(\boldsymbol{X}=\boldsymbol{x}) & \frac{{ }^3 C_3}{{ }^8 C_3} & \frac{{ }^5 C_1 \times{ }^3 C_2}{{ }^8 C_3} & \frac{{ }^5 C_1 \times{ }^3 C_1}{{ }^8 C_3} & \frac{{ }^5 C_3}{{ }^8 C_3} \\\hline\end{array}
\begin{array}{|c|c|c|c|c|}\hline \boldsymbol{X}=\boldsymbol{x} & 0 & 1 & 2 & 3 \\\hline \boldsymbol{P}(\boldsymbol{X}=\boldsymbol{x}) & \frac{1}{56} & \frac{15}{56} & \frac{30}{56} & \frac{10}{56} \\\hline\end{array} Mean $=0 \times \frac{1}{56}+1 \times \frac{15}{56}+2 \times \frac{30}{56}+3 \times \frac{10}{56}=\frac{15}{8}$.
Asked in: AP EAMCET 2024 (21 May Shift 2)
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