An unknown compound A has a molecular formula $\mathrm{C}_{4} \mathrm{H}_{6}$, when $\mathrm{A}$ is treated with an excess of $\mathrm{Br}_{2}$, a new substance $\mathrm{B}$ with formula $\mathrm{C}_{4} \mathrm{H}_{6} \mathrm{Br}_{2}$ is formed. A forms a white precipitate with ammonical silver…

Question

An unknown compound A has a molecular formula $\mathrm{C}_{4} \mathrm{H}_{6}$, when $\mathrm{A}$ is treated with an excess of $\mathrm{Br}_{2}$, a new substance $\mathrm{B}$ with formula $\mathrm{C}_{4} \mathrm{H}_{6} \mathrm{Br}_{2}$ is formed. A forms a white precipitate with ammonical silver nitrate solution. A may be

Aicharya · Accepted Answer

Let us form an equation according to the given condition

$C_{4} H_{6}$ is butyne. It can either be But-1-yne or But-2-yne.
$\mathrm{CH}_{3}-\mathrm{CH}_{2}-C \equiv C H$ But-1-yne
$C H_{3}-C \equiv C-C H_{3}$ But-2-yne
If the triple bond is present with the carbon atom 1 and 2 , then the hydrogen atom is present at C-atom 1 so it is acidic in nature.
$\mathrm{CH}_{3}-C H_{2}-C \equiv C H$ is acidic in nature.
Since Ammoniacal silver nitrate is reducing agent, it reduces butyne, and butyne oxidize ammonical silver, nitrate solution.
We know that oxidation and Reduction occur together.
But-1-yne reduces by tollen's reagent and form white precipitate ,

An unknown compound A has a molecular formula $\mathrm{C}_{4} \mathrm{H}_{6}$, when $\mathrm{A}$ is treated…

Solution