An unbiased coin is tossed 5 times. Suppose that a variable X is assigned the value k when k consecutive heads are obtained for k = 3 , 4 , 5 , otherwise X takes the value - 1 . Then the expected value of X , is

Question

Aicharya · Accepted Answer

If k represents the number of consecutive heads and P k is the corresponding probability while an unbiased coin is tossed 5 times, then k 0 1 2 3 4 5 P k 1 2 5 12 2 5 11 2 5 5 2 5 2 2 5 1 2 5 Now, the expected value of variable X is - 1 1 2 5 + - 1 12 2 5 + - 1 11 2 5 + 3 5 2 5 + 4 2 2 5 + 5 1 2 5 = 1 2 5 - 1 - 12 - 11 + 15 + 8 + 5 = 28 - 24 2 5 = 4 2 5 = 1 2 3 = 1 8

$k$	$0$	$1$	$2$	$3$	$4$	$5$
$P (k)$	$\frac{1}{2^{5}}$	$\frac{12}{2^{5}}$	$\frac{11}{2^{5}}$	$\frac{5}{2^{5}}$	$\frac{2}{2^{5}}$	$\frac{1}{2^{5}}$

An unbiased coin is tossed 5 times. Suppose that a variable X is assigned the value k when k consecutive…

Solution