An organic monobasic acid has dissociation constant $2.25 \times 10^{-6}$. What is percent dissociation in…
An organic monobasic acid has dissociation constant $2.25 \times 10^{-6}$. What is percent dissociation in its $0.01 \mathrm{M}$ solution?
- $1.5 \%$
- $15 \%$
- $5 \%$
- $0.5 \%$
Solution
$\mathrm{K}_{\mathrm{a}}=2.25 \times 10^{-6}$
For a weak monobasic acid,
$\begin{aligned}
\alpha=\sqrt{\frac{\mathrm{K}_{\mathrm{a}}}{\mathrm{c}}}=\sqrt{\frac{2.25 \times 10^{-6}}{0.01}}=\sqrt{2.25 \times 10^{-4}}=0.015 \\
\therefore \quad \text { Percent dissociation }=\alpha \times 100 \\
=0.015 \times 100=1.5 \%
\end{aligned}$
Asked in: MHT CET 2023 (14 May Shift 2)
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