An organic compound is subjected to chlorination to get compound $A$ using $5.0 g$ of chlorine. When $0.5 g$ of compound $A$ is reacted with ${AgNO}_{3}$ [Carius Method], the percentage of chlorine in compound $A$ is when it forms $0.3849 g$ of $AgCl .$ (Round off to the Nearest Integer)
(Atomic masses of $Ag$ and $Cl$ are $107.87$ and $35.5$ respectively)

Question

An organic compound is subjected to chlorination to get compound

A

using

5.0 g

of chlorine. When

0.5 g

of compound

A

is reacted with

{AgNO}_{3}

[Carius Method], the percentage of chlorine in compound

A

is when it forms

0.3849 g

of

AgCl .

(Round off to the Nearest Integer)
(Atomic masses of

Ag

and

Cl

are

107.87

and

35.5

respectively)

Aicharya · Accepted Answer

n Cl in compound = n AgCl = 0 . 3849 &#160; g ( 107 . 87 + 35 . 5 ) g / mol &#8658; mass of chlorine = n Cl &#215; 35 . 5 = 0 . 0953 gm &#8658; % wt. of chlorine = 0 . 0953 0 . 5 &#215; 100 = 19 . 06 %

An organic compound is subjected to chlorination to get compound A using 5 . 0   g of chlorine. When 0 …

Solution

An organic compound is subjected to chlorination to get compound A using 5 . 0 &#160; g of chlorine. When 0 …

Solution

An organic compound is subjected to chlorination to get compound A using 5 . 0 g of chlorine. When 0 …