An organic compound has $\mathrm{C}$ and $\mathrm{H}$ percentage in the ratio $6: 1$ and $\mathrm{C}$ and…

An organic compound has $\mathrm{C}$ and $\mathrm{H}$ percentage in the ratio $6: 1$ and $\mathrm{C}$ and $\mathrm{O}$ percentage in the
ratio $3: 4$ the compound is
  1. $\mathrm{HCHO}$
  2. $\mathrm{CH}_{3} \mathrm{OH}$
  3. $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}$
  4. $(\mathrm{COOH})_{2}$

Solution

$\%$ ratio of $\mathrm{C}: \mathrm{H}$ is $6: 1$ and $\mathrm{C}: \mathrm{O}$ is $3: 4$ or $6: 8$ $\therefore \%$ ratio of $\mathrm{C}: \mathrm{H}: \mathrm{O}$ is $\quad 6: 1: 0$
$($ Total $=15)$
$\%$ of $\mathrm{C}=\frac{6}{15} \times 100=40$
$40 / 12=3.33=1$
$\%$ of $\mathrm{H}=\frac{1}{15} \times 100=6.6$
$6.6 / 1=6.6=2$
$\%$ of $\mathrm{O}=\frac{8}{15} \times 100=53.3$
$53.3 / 16=3.3=1$
simple ratio: $\mathrm{CH}_{2} \mathrm{O}$
$\therefore$ The compound is $\mathrm{HCHO}$ ~

Asked in: JEE-TOPICTESTS-CHEMISTRY

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