An orange precipitate of II group is dissolved in conc. HCl; the solution when treated with excess of water…

An orange precipitate of II group is dissolved in conc. HCl; the solution when treated with excess of water turns milky due to formation of
  1. $\mathrm{Sn}(\mathrm{OH}) \mathrm{Cl}$
  2. $\mathrm{Sb}(\mathrm{OH}) \mathrm{Cl}_{2}$
  3. $\mathrm{SbOCl}$
  4. $\mathrm{Sb}(\mathrm{OH})_{2} \mathrm{Cl}$

Solution

$\begin{aligned} \mathrm{Sb}_{2} \mathrm{~S}_{3}+6 \mathrm{HCl} & ightarrow 2 \mathrm{SbCl}_{3}+3 \mathrm{H}_{2} \mathrm{~S} \\ \mathrm{SbCl}_{3}+6 \mathrm{H}_{2} \mathrm{O} & ightarrow \underset{\text { ppt }(\text { White })}{\mathrm{SbOCl}+2 \mathrm{HCl}} \end{aligned}$ ^

Asked in: JEE-TOPICTESTS-CHEMISTRY

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