An open pipe is suddenly closed at one end. As a result, the frequency of third harmonic of the closed pipe…
An open pipe is suddenly closed at one end. As a result, the frequency of third harmonic of the closed pipe is found to be higher by $100\text{ Hz}$ than that of the fundamental frequency of the open pipe. The fundamental frequency of the open pipe will be [BHU 2012]
200 Hz
240 Hz
300 Hz
480 Hz
Solution
Let $l$ be the length of the pipe and $v$ be the velocity of sound in the air column, then the fundamental frequency of an open pipe $= \frac{v}{2l}$
Fundamental frequency of closed pipe $= \frac{v}{4l}$
Frequency of third harmonic of closed pipe $= \frac{3v}{4l}$
According to given condition,
$\frac{3v}{4l} = \frac{v}{2l} + 100$
$\Rightarrow \frac{v}{2l} = 200\text{ Hz}$