An octahedral complex with molecular composition $\mathrm{M} .5 \mathrm{NH}_{3} \cdot \mathrm{Cl} \cdot…

An octahedral complex with molecular composition $\mathrm{M} .5 \mathrm{NH}_{3} \cdot \mathrm{Cl} \cdot \mathrm{SO}_{4}$ has two isomers,
A and $B$. The solution of $A$ gives a white precipitate with $\mathrm{AgNO}_{3}$ solution and the solution of B gives white precipitate with $\mathrm{BaCl}_{2}$ solution. The type of isomerism exhibited by the complex is:
  1. Linkage isomerism
  2. Ionisation isomerism
  3. Coordinate isomerism
  4. Geometrical isomerism

Solution

The two possible isomers for the given octahedral complex are $\left[\mathrm{M}\left(\mathrm{NH}_{3}ight)_{5} \mathrm{SO}_{4}ight] \mathrm{Cl}$ and $\left[\mathrm{M}\left(\mathrm{NH}_{3}ight)_{5} \mathrm{Cl}ight]$ $\mathrm{SO}_{4}$. They respectively give chloride ion (indicated by precipitation with $\mathrm{BaCl}_{2}$ ) and $\mathrm{SO}_{4}$ ion (indicated by precipitation with $\mathrm{AgNO}_{3}$ ). Hence the type of isomerism exhibited by the complex is ionization isomerism. ^

Asked in: JEE-TOPICTESTS-CHEMISTRY

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