An object requires $500 \mathrm{~N}$ force to be pulled up on a $30^{\circ}$ frictionless smooth inclined…
- $500 \sqrt{2} \mathrm{~N}$
- $1000 \mathrm{~N}$
- $1000 \sqrt{2} \mathrm{~N}$
- $500 \sqrt{3} \mathrm{~N}$
Solution

$\begin{aligned} & \mathrm{mg} \sin 30^{\circ}=500 \mathrm{~N} \\ & \Rightarrow \mathrm{mg} \cdot \frac{1}{2}=500 \mathrm{~N} \\ & \Rightarrow \mathrm{mg}=1000 \mathrm{~N} \\ & \Rightarrow \text { weight }=1000 \mathrm{~N}\end{aligned}$
Asked in: AP EAMCET 2022 (08 Jul Shift 1)