An object of mass 100 kg falls from point $A$ to $B$ as shown in figure. The change in its weight, corrected…
An object of mass 100 kg falls from point $A$ to $B$ as shown in figure. The change in its weight, corrected to the nearest integer is ( $R_E$ is the radius of the earth)
49 N
89 N
5 N
10 N
Solution
$M g^{\prime}=M g \frac{R^2}{(R+h)^2}$
At A $\quad M g^{\prime}=M g \frac{R^2}{(R+2 R)^2}=\frac{M g}{9}$
At $B \quad M g^{\prime}=M g \frac{R}{\left(R+\frac{3 R}{2}\right)^2}=\frac{M g \cdot 4}{25}$
Change in weight $=M g \frac{4}{25}-\frac{M g}{9}=49 \mathrm{~N}$
