An object lying 100 cm inside water is viewed normally from air. If the refractive index of water is…
An object lying 100 cm inside water is viewed normally from air. If the refractive index of water is $\frac{4}{3}$, then the apparent depth of the object is
100 cm
50 cm
25 cm
75 cm
Solution
Real depth $=100 \mathrm{~cm}, \mu=\frac{4}{3}$
$\therefore \quad$ Apparent depth $=\frac{\text { Real depth }}{\mu}=\frac{100 \times 3}{4}=75 \mathrm{~cm}$