An object is projected such that it has to attain maximum range. Another body is projected to reach maximum…
An object is projected such that it has to attain maximum range. Another body is projected to reach maximum height. If both the objects reached the same maximum height, then the ratio initial velocities
$2: 1$
$\sqrt{2}: 1$
$1: \sqrt{2}$
$1: 2$
Solution
For first object, if range is maximum, then
$\theta=45^{\circ}$
$\therefore \mathrm{H}_1=\frac{\mathrm{u}_1^2 \sin ^2 \theta}{2 \mathrm{~g}}=\frac{\mathrm{u}_1^2 \sin ^2 45^{\circ}}{2 \mathrm{~g}}=\frac{\mathrm{u}_1^2}{4 \mathrm{~g}}$
For second object, $\mathrm{H}_2=\frac{\mathrm{u}_2^2}{2 \mathrm{~g}}$
$\therefore \mathrm{H}_1=\mathrm{H}_2 \Rightarrow \frac{\mathrm{u}_1^2}{4 \mathrm{~g}}=\frac{\mathrm{u}_2^2}{2 \mathrm{~g}} \Rightarrow \mathrm{u}_1: \mathrm{u}_2=\sqrt{2}: 1$