An L . C . R . circuit contains resistance of 110   Ω and a supply of 220   V at 300  …

An L.C.R. circuit contains resistance of 110 Ω and a supply of 220 V at 300 rad s-1 angular frequency. If only capacitance is removed from the circuit, current lags behind the voltage by 45°. If on the other hand, the only the inductor is removed the current leads by 45° with the applied voltage. The R.M.S. current flowing in the circuit will be:
  1. 2.5 A
  2. 2 A
  3. 1 A
  4. 1.5 A

Solution

tan45°=1ωCR=ωLR⇒XL=XC

⇒ resonance

i=VR

=220110=2 A

Asked in: JEE Main 2021 (25 Feb Shift 2)

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