An isosceles triangular current carrying loop is kept perpendicularly in a uniform magnetic field…

An isosceles triangular current carrying loop is kept perpendicularly in a uniform magnetic field $\overrightarrow{\mathrm{B}_{\mathrm{o}}}$ as shown in figure. The force on the loop due to magnetic field is

1. ILB $_0 \cos \theta$
2. 2 ILB $_0 \cos \theta$
3. $0$
4. ILB $_0 \sin \theta$

Solution

As the three forces are at $120^{\circ}$ w.r.t. each other as shown above, so $\overrightarrow{\mathrm{F}}_{\text {net }}=0$.

Asked in: AP EAMCET 2022 (05 Jul Shift 2)

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