An iron bar of length $L$ has magnetic moment $M$. It is bent at the middle of its length such that the two…
- $\frac{M}{2}$
- $2 M$
- $\frac{M}{\sqrt{3}}$
- $M$
Solution


$\begin{aligned} & \Delta I=2 \frac{I}{2} \sin 30^{\circ} \\ & =\frac{1}{2} \\ & M^{\prime}=m / / 2 \\ & =M / 2\end{aligned}$
Asked in: NEET 2024
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