An iron bar of length $L$ has magnetic moment $M$. It is bent at the middle of its length such that the two…

An iron bar of length $L$ has magnetic moment $M$. It is bent at the middle of its length such that the two arms make an angle $60^{\circ}$ with each other. The magnetic moment of this new magnet is :
  1. $\frac{M}{2}$
  2. $2 M$
  3. $\frac{M}{\sqrt{3}}$
  4. $M$

Solution



$\begin{aligned} & \Delta I=2 \frac{I}{2} \sin 30^{\circ} \\ & =\frac{1}{2} \\ & M^{\prime}=m / / 2 \\ & =M / 2\end{aligned}$

Asked in: NEET 2024

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