An integrating factor of the differential equation $\left(x^2+1\right) \frac{d y}{d x}+x y=x^3$ is

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Differential equation is $ \begin{aligned} & \frac{d y}{d x}+\left(\frac{x}{1+x^2}ight) y=\frac{x^3}{x^2+1} \ & \mathrm{IF}=e^{\left(\int \frac{x}{1+x^2} d xight)}=e^{\left(\frac{1}{2} \ln \left|1+x^2ight|ight)} \ & =e^{\ln \left(\sqrt{x^2+1}ight.}=\sqrt{x^2+1} \end{aligned} $

An integrating factor of the differential equation $\left(x^2+1\right) \frac{d y}{d x}+x y=x^3$ is

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