An inorganic halide (A) reacts with water to form two acids (B) and (C). (A) also reacts with…

An inorganic halide (A) reacts with water to form two acids (B) and (C). (A) also reacts with $\mathrm{NaOH}$ to form two salts (D) and (E) which remain in solution. The solution gives white precipitate with both $\mathrm{AgNO}_{3}$ and $\mathrm{BaCl}_{2}$ solutions. What is (A)?
  1. $\mathrm{PCl}_{3} \mathrm{~F}_{2}$
  2. $\mathrm{SbCl}_{3}$
  3. $\mathrm{AlCl}_{3}$
  4. $\mathrm{SO}_{2} \mathrm{Cl}_{2}$

Solution

$$
\begin{array}{l}
\mathrm{PCl}_{3} \mathrm{~F}_{2}+\mathrm{H}_{2} \mathrm{O} ightarrow \mathrm{H}_{3} \mathrm{PO}_{4}+\mathrm{HCl}+\mathrm{HF} \\
\mathrm{SbCl}_{3}+\mathrm{H}_{2} \mathrm{O} ightarrow \mathrm{SbOCl}+\mathrm{HCl} \\
\mathrm{AlCl}_{3}+\mathrm{H}_{2} \mathrm{O} ightarrow \mathrm{Al}(\mathrm{OH})_{3}+\mathrm{HCl} \\
\mathrm{SO}_{2} \mathrm{Cl}_{2}+\mathrm{H}_{2} \mathrm{O} ightarrow \mathrm{H}_{2} \mathrm{SO}_{4}+\mathrm{HCl} \\
\mathrm{H}_{2} \mathrm{SO}_{4}+\mathrm{BaCl}_{2} ightarrow \mathrm{BaSO}_{4}(s)
\end{array}
$$ ,

Asked in: JEE-TOPICTESTS-CHEMISTRY

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