An inorganic halide (A) reacts with water to form two acids (B) and (C). (A) also reacts with…
- $\mathrm{PCl}_{3} \mathrm{~F}_{2}$
- $\mathrm{SbCl}_{3}$
- $\mathrm{AlCl}_{3}$
- $\mathrm{SO}_{2} \mathrm{Cl}_{2}$
Solution
\begin{array}{l}
\mathrm{PCl}_{3} \mathrm{~F}_{2}+\mathrm{H}_{2} \mathrm{O} ightarrow \mathrm{H}_{3} \mathrm{PO}_{4}+\mathrm{HCl}+\mathrm{HF} \\
\mathrm{SbCl}_{3}+\mathrm{H}_{2} \mathrm{O} ightarrow \mathrm{SbOCl}+\mathrm{HCl} \\
\mathrm{AlCl}_{3}+\mathrm{H}_{2} \mathrm{O} ightarrow \mathrm{Al}(\mathrm{OH})_{3}+\mathrm{HCl} \\
\mathrm{SO}_{2} \mathrm{Cl}_{2}+\mathrm{H}_{2} \mathrm{O} ightarrow \mathrm{H}_{2} \mathrm{SO}_{4}+\mathrm{HCl} \\
\mathrm{H}_{2} \mathrm{SO}_{4}+\mathrm{BaCl}_{2} ightarrow \mathrm{BaSO}_{4}(s)
\end{array}
$$ ,
Asked in: JEE-TOPICTESTS-CHEMISTRY
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