An ink mark is made on a piece of paper. A glass slab of thickness 't' is placed on it. The ink mark appears…
An ink mark is made on a piece of paper. A glass slab of thickness 't' is placed on it. The ink mark appears to be raised up through a distance ' $x$ ' when viewed at nearly normal incidence. If the refractive index of material of glass slab is ' $\mu$ ' then thickness of glass slab ' $t$ ' is given by
$\frac{(\mu-1)}{\mu \mathrm{x}}$.
$\frac{\mu x}{(\mu-1)}$
$\frac{(\mu-1) x}{\mu}$
$\frac{\mu}{(\mu-1) x}$
Solution
Here, the normal shift is x The formula for the normal shift is
$\begin{aligned}
x & =t\left(1-\frac{1}{\mu}\right) \\
t & =\frac{x}{\left(1-\frac{1}{\mu}\right)} \\
\therefore \quad t & =\frac{\mu x}{(\mu-1)}
\end{aligned}$
.