An information signal of frequency 10 kHz is modulated with a carrier waive of frequency 3.61 MHz. The upper side and lower side frequencies are:

Question

Aicharya · Accepted Answer

For frequency modulated signal, $\begin{aligned} & f_s=10 \mathrm{kHz}, \mathrm{f}_{\mathrm{c}}=3.61 \mathrm{MHz}=3610 \mathrm{kHz} \ & 	herefore \mathrm{f}_{\mathrm{u}}=\mathrm{f}_{\mathrm{c}}+\mathrm{f}_{\mathrm{s}}=3610+10=3620 \mathrm{kHz} \ & \mathrm{f}_1=\mathrm{f}_{\mathrm{c}}-\mathrm{f}_{\mathrm{s}}=3610-10=3600 \mathrm{KHz} \end{aligned}$

An information signal of frequency 10 kHz is modulated with a carrier waive of frequency 3.61 MHz. The upper…

Solution