An infinite number of charge, each of charge \(1 \mu \mathrm{C}\), are placed on the \(x\)-axis with…
Solution

Total force acting on \(1 \mathrm{C}\) charge is given by
\(\begin{aligned} F=\frac{1}{4 \pi \varepsilon_{0}} &\left[\frac{1 \times 1 \times 10^{-6}}{(1)^{2}}+\frac{1 \times 1 \times 10^{-6}}{(2)^{2}}\right.\left.\frac{1 \times 1 \times 10^{-6}}{(4)^{2}}+\frac{1 \times 1 \times 10^{-6}}{(8)^{2}}+\ldots . \infty\right] \end{aligned}\)
\(=\frac{10^{-6}}{4 \pi \varepsilon_{0}}\left(\frac{1}{1}+\frac{1}{4}+\frac{1}{16}+\frac{1}{64}+\ldots . \infty\right)\)
\(\quad=9 \times 10^{9} \times 10^{-6}\left(\frac{1}{1-\frac{1}{4}}\right)\)
\(=9 \times 10^{9} \times 10^{-6} \times \frac{4}{3}=9 \times \frac{4}{3} \times 10^{3}=12000 \mathrm{~N}=12 \mathrm{kN}\)
Asked in: JEE Mains - Electrostatics - Chapter Test