An inductor of 0 . 5   mH , a capacitor of 20   μF and resistance of 20   Ω are…

Here, emf and current are in phase, so the circuit is either pure resistive circuit or case of resonance,

$X_L=X_C$

Thus, the impedance of circuit is  $Z=\sqrt{R^2+{\left(X_L-X_C\right)}^2}=R=20 \mathrm{\Omega }$

Now, rms value of current is $i_{\mathrm{rms}}=\frac{220}{20}=11 \mathrm{A}$

Using the relation between peak and rms value of current, we have peak value $i_{0=}{i}_{\mathrm{rms}}\sqrt{2}=11\sqrt{2}=\sqrt{242} \mathrm{A}$.

Hence, the value of $x=242$.