An inductor is connected to an ac source of frequency 50 $\mathrm{Hz}$. The frequency of the instantaneous power developed in the circuit is

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Aicharya · Accepted Answer

For $\mathrm{AC}$ circuit containing inductor only. $\begin{aligned} & I=I_0 \sin \omega t \ & V=V_0 \sin \left(\omega t+\frac{\pi}{2}ight)=V_0 \cos \omega t\end{aligned}$ So, power, $\mathrm{P}=\mathrm{VI}$ $\begin{aligned} & =V_0 \operatorname{Cos} \omega t I_0 \sin \omega t \ & =\frac{V_0 I_0}{2} \sin 2 \omega t\end{aligned}$ Clearly the frequency becomes 2 times. $\mathrm{f}^{\prime}=2 \mathrm{f}=2 	imes 50=100 \mathrm{~Hz}$

An inductor is connected to an ac source of frequency 50 $\mathrm{Hz}$. The frequency of the instantaneous…

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