An inductor coil of inductance $L$ is divided into two parts and both parts are connected in parallel. The…

An inductor coil of inductance $L$ is divided into two parts and both parts are connected in parallel. The net inductance is
  1. L
  2. 2 L
  3. $\frac{\mathrm{L}}{2}$
  4. $\frac{\mathrm{L}}{4}$

Solution

Inductance is proportional to the length of the coil so each part will have inductance $\frac{\mathrm{L}}{2}$ Net inductance $=\frac{\mathrm{L}_1 \mathrm{~L}_2}{\mathrm{~L}_1+\mathrm{L}_2}=\frac{\frac{\mathrm{L}}{2} \times \frac{\mathrm{L}}{2}}{\frac{\mathrm{~L}}{2}+\frac{\mathrm{L}}{2}}=\frac{\mathrm{L}}{4}$

Asked in: MHT CET 2024 (10 May Shift 1)

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