An inductor and a resistor of $25 \Omega$ are connected in series to an ac source of voltage $100 \sin (100…
An inductor and a resistor of $25 \Omega$ are connected in series to an ac source of voltage $100 \sin (100 \pi \mathrm{t})$ volt. If the impedance of the circuit is $50 \Omega$, the average power dissipated per cycle in the circuit is
$10 \mathrm{~W}$
$25 \mathrm{~W}$
$50 \mathrm{~W}$
$100 \mathrm{~W}$
Solution
The average power dissipated per cycle in the circuit
$\mathrm{P}=\frac{\mathrm{V}^2}{\mathrm{Z}^2} \mathrm{R}=\frac{100^2}{50^2} \times 25=100 \mathrm{~W}$