An inductance coil has a reactance of 100   Ω . When an AC signal of frequency 1000   Hz is…

An inductance coil has a reactance of 100 Ω . When an AC signal of frequency 1000 Hz is applied to the coil, the applied voltage leads the current by 45°. The self-inductance of the coil is
  1. 1.1×10-2 H
  2. 1.1×10-1 H
  3. 5.5×10-5 H
  4. 6.7×10-7 H

Solution

tanθ=xLR=tan45°
xL=R
=100=xL2+R2
100=R2+R2
2R=100
R=502
∴xL=502
Lω=502
L=5022π×1000=252πmH
=1.1×10-2H

Asked in: JEE Main 2020 (02 Sep Shift 2)

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