An imaginary equilateral triangle A B C of side length 2   m is placed in a uniform electric field E…

An imaginary equilateral triangle ABC of side length 2 m is placed in a uniform electric field E→=10 N C-1 as shown. Then. VA-VB=

  1. -5 V
  2. +5 V
  3. -10 V
  4. +10 V

Solution

Here angle  ϕ=60°

Potential difference in uniform electric field is given by

∆v=-Ercosϕ

⇒∆v=-10×2cos60=-10 v

Asked in: AP EAMCET 2020 (23 Sep Shift 1)

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