An ideal transformer is used to set up an alternating e.m.f. of $220 \mathrm{~V}$ to $4.4 \mathrm{kV}$ to…

An ideal transformer is used to set up an alternating e.m.f. of $220 \mathrm{~V}$ to $4.4 \mathrm{kV}$ to transmit $6.6 \mathrm{~kW}$ of power. The primary coil has 100 turns. What is current rating of secondary?
  1. $1.0 \mathrm{~A}$
  2. 0.75 A
  3. $2.5 \mathrm{~A}$
  4. $1.5 \mathrm{~A}$

Solution

$\begin{aligned} & P_0=V_s i_s \\ & 6.6=4.4 \times i_s \Rightarrow i_s=1.5 \mathrm{~A}\end{aligned}$

Asked in: MHT CET 2022 (06 Aug Shift 1)

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