An ideal monatomic gas is taken round the cycle $\mathrm{ABCD}$ as shown in the fig. The work done during…
An ideal monatomic gas is taken round the cycle $\mathrm{ABCD}$ as shown in the fig. The work done during the cycle is
- $p V$
- $2 p V$
- $\frac{1}{2} p V$
- zero
Solution
The work done during the cyclic path is equal to the area enclosed by the path, which is, $p V$.
Asked in: JEE-TOPICTESTS-CHEMISTRY
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