An ideal gas undergoes a four step cycle as shown in the P - V diagram below. During this cycle, heat is…

$\because PV=nRT ...\left(1\right)$

In Step $1$:

$P=$constant

$V=$ increasing

So,

$T$ also will be increase (From equation $1$)

Now, 

$\because Q=n{C}_p∆T$

$\because T \uparrow$

$\therefore ∆T=$ Positive

So,

 $Q=+ve=$absorbed

Now In step $4$,

$P=\uparrow$

$V=$ constant

So from equation $1$,

$T$ will also be increasing.

Now, $\because Q=n{C}_v∆T$

$\because T\uparrow$

$\therefore ∆T=$Positive

So, 

$Q=+ve=$absorbed

correct option is $\left(3\right)$.