An ideal gas is taken through the cycle \(A \rightarrow\) \(B \rightarrow C \rightarrow A\) as shown in the figure. If the net heat supplied to the gas in the cycle is \(5 \mathrm{~J}\). The magnitude of work done during the process \(C \rightarrow A\) is

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Aicharya · Accepted Answer

An ideal gas is taken through the cycle \(A \rightarrow B \rightarrow C \rightarrow A\) as shown in the figure,

From the graph, \(\begin{aligned} W_{A B} & =P \times d V \\ & =10 \times(2-1)=10 \mathrm{~J} \end{aligned}\) Similarly, \(W_{B C}=P \times(0)=0 \mathrm{~J}\) According to the first law of thermodynamics \(\Delta Q=\Delta U+W\) Here, \(\Delta U = 0\) \(\begin{aligned} & \therefore \quad Q=W \\ & 5=W_{A B}+W_{B C}+W_{C A} \\ & W_{C A}=5-W_{A B}-W_{B C}=5-10-0 \\ & W_{C A}=-5 \mathrm{~J} \\ & \therefore \quad\left|W_{C A}\right|=5 \mathrm{~J} \\ \end{aligned}\) Hence, the magnitude of work done during the process \(C \rightarrow A\) is \(5 \mathrm{~J}\).

An ideal gas is taken through the cycle \(A \rightarrow\) \(B \rightarrow C \rightarrow A\) as shown in the…

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