An ideal gas is allowed to expand from $2 \mathrm{dm}^3$ to $6 \times 10^{-3} \mathrm{~m}^3$ against a…

An ideal gas is allowed to expand from $2 \mathrm{dm}^3$ to $6 \times 10^{-3} \mathrm{~m}^3$ against a constant external pressure of 1 bar. The work done in $\mathrm{kJ}$ is
  1. -6.0 kJ
  2. -0.4 kJ
  3. -4.0 kJ
  4. -2 kJ

Solution

$\begin{aligned} \mathrm{W} & =-\mathrm{P}\left(\mathrm{V}_2-\mathrm{V}_1\right) \\ & =-\left(6 \times 10^{-3}-2 \times 10^{-3}\right) \mathrm{bar}-\mathrm{m}^3 \\ & =-4 \times 10^{-3} \times 10^5 \frac{\mathrm{N}}{\mathrm{m}^2}-\mathrm{m}^3 \\ & =-400 \mathrm{~J}=-0.4 \mathrm{KJ}\end{aligned}$

Asked in: MHT CET 2022 (11 Aug Shift 1)

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