An ideal gas heat engine operates in a Carnot's cycle between $227^{\circ} \mathrm{C}$ and $127^{\circ}…

An ideal gas heat engine operates in a Carnot's cycle between $227^{\circ} \mathrm{C}$ and $127^{\circ} \mathrm{C}$. It absorbs $6 \times 10^{4}$ J at high temperature. The amount of heat converted into work is
  1. $4.8 \times 10^{4} \mathrm{~J}$
  2. $35 \times 10^{4} \mathrm{~J}$
  3. $1.6 \times 10^{4} \mathrm{~J}$
  4. $1.2 \times 10^{4} \mathrm{~J}$

Solution

Given, amount of heat absorbed, $Q=6 \times 10^{4} \mathrm{~J}$ Temperature of reservoir, $T_{1}=227^{\circ} \mathrm{C}=227+273 \mathrm{~K}$ $=500 \mathrm{~K}$ Temperature of $\operatorname{sink}, T_{2}=127^{\circ} \mathrm{C}$ $\begin{aligned} &=127+273 \mathrm{~K} \\ &=400 \mathrm{~K} \end{aligned}$ Efficiency of Carnot engine, $\eta=1-\frac{T_{2}}{T_{1}}$ $=1-\frac{400}{500}=\frac{1}{5}$ Work done by Carnot engine $(W)$ $\begin{aligned} &=\text { Efficiency }(\eta) \times \text { heat absorbed }(Q) \\ W & {\left[\eta=\frac{W}{Q}\right] } \\ W &=\frac{1}{5} \times 6 \times 10^{4} \mathrm{~J}=1.2 \times 10^{4} \mathrm{~J} \end{aligned}$

Asked in: TEST SERIES MHT-CET Full Test 6

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