An ideal gas expands isothermally from volume $V_1$ to volume $V_2$. It is then compressed to the original…
- $p_1>p_2, W=0$
- $p_1>p_2, W>0$
- $p_2>p_1, W>0$
- $p_2>p_1, W < 0$
Solution

From graph it is clear that, $p_2>p_1$. Since, area under adiabatic process (BCED) is greater than that of isothermal process ( $A B D E)$. Therefore, net work done $\because \quad W_A>W_1$ $\Rightarrow \quad W < 0$ Hence option (d) is correct.
Asked in: AP EAMCET 2010