An ideal gas expands from $1 \times 10^{-3} \mathrm{~m}^{3}$ to $1 \times 10^{-2} \mathrm{~m}^{3}$ at $300…

An ideal gas expands from $1 \times 10^{-3} \mathrm{~m}^{3}$ to $1 \times 10^{-2} \mathrm{~m}^{3}$ at $300 \mathrm{~K}$ against a constant external pressure of $1 \times 10^{5} \mathrm{~nm}^{-2}$, work done is
  1. $-9 \times 10^{2} \mathrm{~J}$
  2. $-9 \times 10^{3} \mathrm{~J}$
  3. $-0.7 \times 10^{3} \mathrm{~J}$
  4. $-1 \times 10^{3} \mathrm{~J}$(a)

Solution

$\begin{aligned} V_{1} &=1 \times 10^{-3} \mathrm{~m}^{3}=0.001 \mathrm{~m}^{3} \\ V_{2} &=1 \times 10^{-2} \mathrm{~m}^{3}=0.01 \mathrm{~m}^{3} \\ P_{\mathrm{ex}} &=1 \times 10^{5} \mathrm{Nm}^{-2} \\ W &=-P_{\mathrm{ex}}\left(V_{2}-V_{1}\right)=-1 \times 10^{5}(0.01-0.001) \\ &=-0.009 \times 10^{5} \\ W &=-9 \times 10^{2} \mathrm{~J} \end{aligned}$

Asked in: MHT CET 2020 (15 Oct Shift 2)

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