An ideal gas expands by performing $200 \mathrm{~J}$ of work, during this internal energy increases by $432 \mathrm{~J}$. What is enthalpy change?

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Aicharya · Accepted Answer

Assuming constant pressure, $\Delta \mathrm{H}=\Delta \mathrm{U}+\mathrm{P}_{\mathrm{ext}} \Delta \mathrm{V}=\Delta \mathrm{U}-\mathrm{W}$ Work done $(\mathrm{W})=-200 \mathrm{~J}$ (for expansion of a gas) $\begin{aligned} & \Delta \mathrm{U}=+432 \mathrm{~J} \ & \Delta \mathrm{H}=\Delta \mathrm{U}-\mathrm{W}=+432-(-200)=+632 \mathrm{~J} \end{aligned}$

An ideal gas expands by performing $200 \mathrm{~J}$ of work, during this internal energy increases by $432…

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