An ideal coil of $10 \mathrm{H}$ is connected in series with a resistance of $5 \Omega$ and a battery of $5…

An ideal coil of $10 \mathrm{H}$ is connected in series with a resistance of $5 \Omega$ and a battery of $5 \mathrm{~V}$. $2$ second after the connection is made the current flowing in amperes in the circuit is
  1. $(1-\mathrm{e})$
  2. $\mathrm{e}$
  3. $\mathrm{e}^{-1}$
  4. $\left(1-\mathrm{e}^{-1}\right)$

Solution

$\mathrm{i}=\mathrm{i}_0\left(1-\mathrm{e}^{\frac{\mathrm{Rt}}{\mathrm{L}}}\right)$ $=\left(1-\mathrm{e}^{-1}\right)$

Asked in: JEE Main 2007

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