An expression of energy density is given by u = α β sin α x k t , where α ,   β are constants, x is displacement, k is Boltzmann constant and t is the temperature. The dimensions of β will be

Question

An expression of energy density is given by u = &#945; &#946; sin &#945; x k t , where &#945; , &#160; &#946; are constants, x is displacement, k is Boltzmann constant and t is the temperature. The dimensions of &#946; will be

Aicharya · Accepted Answer

Given that energy density U = &#945; &#946; sin &#945; x k t As &#945; x k t should be dimensionless, the dimensions of &#945; x and k t should be same. &#8658; &#945; x = k t &#8658; &#945; = k t x Now, U = &#945; &#946; &#8658; &#946; = &#945; U = k t x E V = E t t x E V &#8658; &#946; = L 3 L = M 0 L 2 T 0

An expression of energy density is given by u = α β sin α x k t , where α ,   &#946…

Solution

An expression of energy density is given by u = &#945; &#946; sin &#945; x k t , where &#945; , &#160; &#946…

Solution

An expression of energy density is given by u = α β sin α x k t , where α , &#946…