An ester is boiled with $\mathrm{KOH}$. The product is cooled and acidified with concentrated HCl. A white…
An ester is boiled with $\mathrm{KOH}$. The product is cooled and acidified with concentrated HCl. A white crystalline acid separates. The ester is
methyl acetate
ethyl acetate
ethyl formate
ethyl benzoate
Solution
Ethyl benzoate on hydrolysis gives benzoic acid which is a solid, other esters give $\mathrm{CH}_{3} \mathrm{COOH}$ and HCOOH, both of which are liquids.